operator&,|,^(std::bitset)
From cppreference.com
| Defined in header <bitset>
|
||
template< std::size_t N >
std::bitset<N> operator&( const std::bitset<N>& lhs,
const std::bitset<N>& rhs );
|
(1) | (noexcept since C++11) (constexpr since C++23) |
template< std::size_t N >
std::bitset<N> operator|( const std::bitset<N>& lhs,
const std::bitset<N>& rhs );
|
(2) | (noexcept since C++11) (constexpr since C++23) |
template< std::size_t N >
std::bitset<N> operator^( const std::bitset<N>& lhs,
const std::bitset<N>& rhs );
|
(3) | (noexcept since C++11) (constexpr since C++23) |
Performs binary AND, OR, and XOR between two bitsets, lhs and rhs.
1) Returns a
std::bitset<N> containing the result of binary AND on corresponding pairs of bits of lhs and rhs.2) Returns a
std::bitset<N> containing the result of binary OR on corresponding pairs of bits of lhs and rhs.3) Returns a
std::bitset<N> containing the result of binary XOR on corresponding pairs of bits of lhs and rhs.Parameters
| lhs | - | the bitset on the left-hand side of the operator |
| rhs | - | the bitset on the right-hand side of the operator |
Return value
1)
std::bitset<N>(lhs) &= rhs2)
std::bitset<N>(lhs) |= rhs3)
std::bitset<N>(lhs) ^= rhsExample
Run this code
#include <bitset>
#include <iostream>
int main()
{
std::bitset<4> b1("0110");
std::bitset<4> b2("0011");
std::cout << "b1 & b2: " << (b1 & b2) << '\n';
std::cout << "b1 | b2: " << (b1 | b2) << '\n';
std::cout << "b1 ^ b2: " << (b1 ^ b2) << '\n';
}
Output:
b1 & b2: 0010
b1 | b2: 0111
b1 ^ b2: 0101
See also
| performs binary AND, OR, XOR and NOT (public member function) |